First let's take a look at the string.find function in general:. lua documentation: string.find (Introduction) Example The find function. s:gsub('%a+', ' %1 '):gsub(' (%u+) ', print) --> THE QUICK JUMPS The pattern can be extended to more general statements: "Find all words that are at least four characters and are … The cool thing is that Lua is a 300KB download, if you want to test patterns out without going through Rust. You specify a capture by writing the parts of the pattern that you want to capture between parentheses. R gsub. On Wed, Jan 5, 2011 at 8:40 AM, Steve Litt wrote: > So what do you think -- how do you represent tab or "anything but tab" in a > Lua pattern? 20.3 – Captures. This section describes the syntax and the meaning (that is, what they match) of these strings. Patterns in Lua are described by regular strings, which are interpreted as patterns by the pattern-matching functions string.find, string.gmatch, string.gsub, and string.match. local foo = "12345678bar123" print(foo:match "%d+") --> … パターン pattern をすべて repl によって指定された置換文字列に置き換えた s のコピーを返す。 repl は文字列、テーブル、または関数でもよい。 gsub は二番目の値として、置換が行われた回数も返す。 repl が文字列であれば、その値が置換に使われる。 But the gsub function seems to be never taking in the I've organized the Rust interface much as the original Lua library, 'match', 'gmatch' and 'gsub', but made these methods of a LuaPattern struct. gsub() function replaces all matches of a string, if the parameter is a string vector, returns a string vector of the same length and with the same attributes (after possible coercion to character). In the following Lua code, I attempt to implement a selector syntax that changes its value based on the Minecraft "world" a "wood" is found in. The capture mechanism allows a pattern to yank parts of the subject string that match parts of the pattern, for further use. 文字+はシーケンス内の1つ以上の一致した文字を表し、常に最も長い時間一致したシーケンスを返します。. translated from the lua documentstring.gsub用法:函数原型:string.gsub( s, pattern, rep1[, n] )函数功能:返回一个和pattern匹配,并且用rep1替换的副本。 rep1可以是string、table和functin。 translated from the lua document string.gsub用法: 函数原型:string.gsub( s, pattern, rep1[, n] ) 函数功能:返回一个和 lua documentation: ルアパターンマッチング. The function string.find (s, substr [, init [, plain]]) returns the start and end index of a substring if found, and nil otherwise, starting at the index init if it is provided (defaults to 1). 以下内容翻译自《Lua 5.3 Reference Manual》6.4.1 - Patterns。 ----- 我是一条分割线----- Lua中的模式匹配用正则表达式来描述,它被用于string.find, string.gmatch, string.gsub, 和 string.match.匹配一种模式。本结将讲述它的语法和模式字符串所代表的意思(及,它所匹配的字符串)。

Elements of string vectors which are not substituted will be …